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In ΔABC, ∠A = 90°, AD ┴ BC and AD = BD = 2 cm. The length of CD is
Given : AD = BD = 2 cm
Let CD = $$x$$ cm
Using, $$(AD)^2 = (BD) \times (CD)$$
=> $$(2)^2 = 2 \times x$$
=> $$x = \frac{4}{2} = 2$$ cm
=> Ans - (D)
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