In a $$\triangle ABC$$, if $$\angle A= 90^{\circ}$$, AC= 5 cm, BC= 9 cm and in $$\triangle PQR, LP= 90^{\circ}$$, PR = 3 cm, QR= 8 cm, then:

A

$$\triangle \cong \triangle PQR$$

B

$$\triangle \ncong \triangle PQR$$

C

$$\triangle \neq \triangle PQR$$

D

$$\triangle = \triangle PQR$$