In a $$\triangle ABC, DE \parallel BC$$, where D is a point on AB and E is a point on AC. If DE divides the area of $$\triangle ABC$$ into two equal parts, then $$DB : AB$$ is equal to:

A

$$\sqrt{2} : \sqrt{3}$$

B

$$\sqrt{2} : \sqrt{2} + 1$$

C

$$\sqrt{2} + 1 : \sqrt{2}$$

D

$$\sqrt{2} - 1 : \sqrt{2}$$