Question 61

If $$\ x^{2}+9y^{2}\ $$= 6xy, then x: y is

$$x^{2}+9y^{2}$$=6xy


$$\Rightarrow x^{2}-6xy+9y^{2}$$=0


$$\Rightarrow (x-3y)^{2}$$=0


$$\Rightarrow$$ x-3y=0


$$\Rightarrow$$ x=3y


$$\Rightarrow \frac{x}{y}$$=$$\frac{3}{1}$$


$$\therefore$$ x:y=3:1

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