If the length of a chord of a circle is equal to that of the radius of the circle, then the angle subtended, in radians, at the centre of the circle by chord is
As the length of a chord of a circle is equal to that of the radius of the circle, thus triangle formed will be equilateral triangle.
Thus, the three angles will be equal to $$60^\circ$$
= $$\frac{\pi}{3}$$
=> Ans - (C)
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