If $$\sec^{2}A+\tan^{2}A=\frac{4}{17}$$, then $$\sec^{4}A-\tan^{4}A$$ is equal to:

A

$$\frac{4}{17}$$

B

$$\frac{5}{17}$$

C

$$\frac{13}{17}$$

D

$$\frac{4}{13}$$