If $$7b - \frac{1}{4b} = 7$$, then what is the value of $$16b^2 + \frac{1}{49b^2}$$?

A

$$\frac{80}{49}$$

B

$$\frac{104}{7}$$

C

$$\frac{120}{7}$$

D

$$\frac{7}{2}$$