The simplified value of $$\frac{109-\left\{121\div\left(11 of 11\right)-\left(-4\right)-\left(3-\overline{8-1}\right)\right\}}{125-\left(-3\right)\left(4-\overline{6-2}\right)\div3\left\{5+\left(-3\right) of \left(-6\right)\right\}}$$ is:

A

125

B

$$\frac{4}{5}$$

C

100

D

$$\frac{5}{4}$$