Question 60
Let p and q be inversely proportional and positive. If p increases by 20%, then q decreases by
Solution
Let $$p=\frac{1}{q}$$
If $$p$$ increases by 20%, => $$p'=\frac{6p}{5}=\frac{6}{5q}$$
Now, $$p'=\frac{1}{q'}$$
=> $$q'=\frac{1}{p'}$$
=> $$q'=\frac{5q}{6}$$
$$\therefore$$ Percentage decrease in $$q=\frac{1}{6}\times100=16\frac{2}{3}\%$$
=> Ans - (D)
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