Question 60

Let p and q be inversely proportional and positive. If p increases by 20%, then q increases by

Solution

Let $$p=\frac{1}{q}$$

If $$p$$ increases by 20%, => $$p'=\frac{6p}{5}=\frac{6}{5q}$$

Now, $$p'=\frac{1}{q'}$$

=> $$q'=\frac{1}{p'}$$

=> $$q'=\frac{5q}{6}$$

$$\therefore$$ Percentage decrease in $$q=\frac{1}{6}\times100=16\frac{2}{3}\%$$

=> Ans - (D)

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