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Question 61
If r is the remainder when each of 1059, 1417 and 2312 is divided by k, where k is an integer greater than 1, then the value of d+k is
Solution
Since, each has the same remainder, we need to find the H.C.F. [(1417-1059),(2312-1417),(2312-1059)]
= H.C.F. (358,895,1253) = 179
Now, when we divide 1059, 1417 and 2312 by 179, we get remainder as 164
$$\therefore$$ $$r+k=164+179=343$$
=> Ans - (C)
