In $$\triangle ABC$$, AB = AC, O is a point on BC such that BO = CO and OD is perpendicular to AB and OE is perpendicular to AC. If $$\angle BOD=60^{0}$$, then measure of $$\angle AOE$$ is:

A

$$120^{0}$$

B

$$60^{0}$$

C

$$30^{0}$$

D

$$90^{0}$$