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If a, 1, b are in arithmetic progression and 1, a, b are in geometric progression, then a and b are respectively
equate to _______ (where a ≠ b).
$$a,\ 1,\ b$$ are in AP.
$$a+b=2$$
$$1,\ a,\ b$$ are in GP.
$$a^2=\left(1\times b\right)=b$$
$$a^2+a-2=0$$
$$a^2+2a-a-2=0$$
$$\left(a+2\right)\left(a-1\right)=0$$
$$a=1,\ -2$$
$$b=1,\ 4$$
It is given that $$a$$ and $$b$$ are not equal.
Hence, a = -2 and b = 4.
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