Question 61
Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km
respectively. What is the time taken by the slower train to cross the faster train in seconds?
Solution
distance = total length = 1.10 km +0.9 km
= 2km
=2000 m
relative speed = 60 km/hr + 90 km/hr
= 150 km/hr
change into m/s = $$150\frac{5}{18}= \frac{125}{3}$$
time = $$distance\times speed$$
= $$2000\times \frac{125}{3}$$
=48 sec
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