Question 6

The number of positive divisors of 1995 is:

Solution

Share

1995 = 5$$^1$$ x 3$$^1$$ x 19$$^1$$ x 7$$^1$$

$$\therefore\ $$Number of factors of 1995 = (1+1)(1+1)(1+1)(1+1) = 2 x 2 x 2 x 2 = 16

Hence, the correct answer is Option B

Was this solution helpful?

Get AI Help

Create a FREE account and get:

  • Download Maths Shortcuts PDF
  • Get 300+ previous papers with solutions PDF
  • 500+ Online Tests for Free

Join CAT 2026 course by 5-Time CAT 100%iler

Start your IIM journey with the right preparation and crack CAT 2026.

Enroll Now
Ask AI