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What is the area $$(in cm^2)$$ of a square having perimeter 84 cm?
Let side of square = $$s$$ cm
=> Perimeter = $$4s=84$$
=> $$s=\frac{84}{4}=21$$ cm
$$\therefore$$ Area of square = $$s^2=(21)^2=441$$ $$cm^2$$
=> Ans - (D)
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