Newton-Raphton iteration formula for finding $$\sqrt[3]{C}$$, where $$C > 0$$ is

A

$$x_{n + 1} = \frac {2x_n^3 + \sqrt[3]{C}} {3x_n^2}$$

B

$$x_{n + 1} = \frac {2x_n^3 - \sqrt[3]{C}} {3x_n^2}$$

C

$$x_{n + 1} = \frac {2x_n^2 + {C}} {3x_n^2}$$

D

$$x_{n + 1} = \frac {2x_n^2 - {C}} {3x_n^2}$$