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Newton-Raphton iteration formula for finding $$\sqrt[3]{C}$$, where $$C > 0$$ is
$$x_{n + 1} = \frac {2x_n^3 + \sqrt[3]{C}} {3x_n^2}$$
$$x_{n + 1} = \frac {2x_n^3 - \sqrt[3]{C}} {3x_n^2}$$
$$x_{n + 1} = \frac {2x_n^2 + {C}} {3x_n^2}$$
$$x_{n + 1} = \frac {2x_n^2 - {C}} {3x_n^2}$$
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