In $$\triangle$$ ABC, AB = 7 cm. BC = 10 cm. and AC= 8 cm. If AD is the angle bisector of $$\angle$$ BAC, where D is a point on BC, then $$\frac{DC}{4}$$ (in cm) is equal to:

A

$$\frac{14}{3}$$

B

$$\frac{4}{3}$$

C

$$\frac{11}{3}$$

D

$$\frac{7}{3}$$