Solution
Given : $$m+n=1$$ ------------(i)
Cubing both sides
=> $$(m+n)^3=(1)^3$$
=> $$m^3+n^3+3mn(m+n)=1$$
Using equation (i), we get :
=> $$m^3+n^3+3mn(1)=1$$
=> $$m^3 + n^3 + 3mn=1$$
=> Ans - (B)
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