A runs at a speed that is $$\frac{11}{9}$$ times the speed of B. If B is allowed to have a head start such that B beats A by $$\frac{1}{3}$$ of the length of the race, what part of the length of the race has been given as head start to B over A?
(Note: Consider A and B to start running at the same time.]

A

$$\frac{3}{11}$$

B

$$\frac{22}{27}$$

C

$$\frac{6}{11}$$

D

$$\frac{5}{11}$$