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Question 58
What is the value of $$1040 \div 65 - 8 \times \frac{1}{2} of \left(\frac{1}{2} - \frac{1}{3}\right)$$?
Solution
$$1040 \div 65 - 8 \times \frac{1}{2} of \left(\frac{1}{2} - \frac{1}{3}\right) = \dfrac{1040}{65} - 8 \times \dfrac{1}{2} \text{of} \dfrac{1}{6} = \dfrac{1040}{65} - 8 \times \dfrac{1}{12} = 16 - \dfrac{2}{3} = \dfrac{48-2}{3} = \dfrac{46}{3}$$
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