If $$x-\frac{1}{3x}=\frac{1}{3}$$, the value of $$3(x-\frac{1}{3x})$$ is
$$x-\frac{1}{3x}=\frac{1}{3}$$
now $$3\left(x-\frac{1}{3x}\right)=3\times\ \frac{1}{3}=1$$
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