If $$\tan 40^\circ = \alpha$$, then Find $$\frac{\tan 320^\circ - \tan 310^\circ}{1 + \tan 320^\circ . \tan 310^\circ}$$.

A

$$\frac{1 - \alpha^2}{\alpha}$$

B

$$\frac{1 + \alpha^2}{2 \alpha}$$

C

$$\frac{1 - \alpha^2}{2 \alpha}$$

D

$$\frac{1 + \alpha^2}{\alpha}$$