If $$(4x - 5)^3 + (x - 2)^3 + 27(2x - 5)^3 = 9(4x - 5)(x - 2)(2x - 5)$$, then the value of $$\left(x + \frac{3}{2}\right)$$ will be:

A

$$\frac{3}{2}$$

B

$$\frac{1}{2}$$

C

$$\frac{7}{2}$$

D

$$\frac{5}{2}$$