Ellingham diagrams are plots of $$\Delta G^0$$ vs temperature which have applications in metallurgy. For $$2H_2 + O_2 \rightarrow 2H_2O$$, $$\Delta G (J) = -247500 + 55.85T$$ (I), and for $$2CO + O_2 \rightarrow 2CO_2$$, $$\Delta G (J) = -282400 + 86.81T$$ (II). The Ellingham diagrams for the oxidation of $$H_2$$ (I) and CO (II) are given below and the two lines intersect at $$T_E = 1125$$ K.
[image]
Which of the following is correct? I. $$\Delta G^0$$ for reaction (i) is more negative at $$T < 1125$$ K II. $$\Delta G^0$$ for the reduction of CO is more negative at $$T < 1125$$ K III. $$H_2$$ is a better reducing agent at $$T > 1125$$ K IV. $$H_2$$ is a better reducing agent at $$T < 1125$$ K