The length of the diagonal of a rectangle is 26 cm and that of one side is 10 cm. What is the area of this rectangle?
Let breadth of the rectangle $$b$$ = 10 cm and diagonal $$d$$ = 26 cm
Let length of rectangle = $$l$$ cm
Using, $$(l)^2 + (b)^2 = (d)^2$$
=> $$(l)^2 + (10)^2 = (26)^2$$
=> $$(l)^2 = 676 - 100 = 576$$
=> $$l = \sqrt{576} = 24$$ cm
$$\therefore$$ Area of rectangle = $$l \times b$$
= $$24 \times 10 = 240 cm^2$$
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