Sign in
Please select an account to continue using cracku.in
↓ →
Out of four numbers the average of the first three is 16 and that of the last three is 15. If the last number is 21 then the first number is:
let the four numbers be a,b,c,d
given that the average of first 3 numbers is 16
i.e; (a+b+c)/3=16
average of last three numbers is 15
i.e; (b+c+d)/3=16
given that last number is 21
therefore b+c+21=16$$\times\ $$3
b+c=48-21
b+c=24
we know that a+b+c=48
=>24+a=48 (since b+c=24)
therefore a=24
hence answer is option D
Was this solution helpful?
Create a FREE account and get:
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
91- 6303239042
