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Manjeet can do a work in 18 hours. If he is joined by Jaya who is 100% more efficient, in what time will they together finish the work?
Let total work to be done = 18 units
Manjeet's efficiency = $$\frac{18}{18} = 1$$ unit/hr
Jaya is 100% more efficient, => Jaya's efficiency = $$1 + \frac{100}{100} \times 1 = 2$$ units/hr
(Manjeet + Jaya)'s 1 day's work together = 1 + 2 = 3 units/hr
$$\therefore$$ Time taken by Manjeet and Jaya together to finish the work = $$\frac{18}{3} = 6$$ hours
=> Ans - (A)
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