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Question 57

In the reaction,

The product E is

Solution

Step 1: Diazotization (Formation of Intermediate D)

Step 2: Sandmeyer Reaction (Formation of Product E)

Reaction:

$$p\text{-}CH_3C_6H_4NH_2 \xrightarrow{NaNO_2/HCl, 0\text{--}5^\circ C} p\text{-}CH_3C_6H_4N_2^+Cl^- (D)$$

$$p\text{-}CH_3C_6H_4N_2^+Cl^- (D) \xrightarrow{CuCN/KCN, \Delta} p\text{-}CH_3C_6H_4CN (E) + N_2$$

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