If $$x + y + z = 5, \frac{1}{x} + \frac{1}{y} + \frac{1}{z} = 0, xyz = 12$$ and $$x^3 + y^3 + z^3 = 151$$, then the value of $$(x^2 + y^2 + z^2)$$ is:

A

24

B

23

C

22

D

21