18 men can complete a work in 9 days. After they have worked for 5 days, 6 more men join them. How many days will they take to complete the remaining work ?
Total number of work =Â $$18\times\ 9=162\ \ units$$
Number of work done in 5 days by 18 men =Â $$18\times\ 5=90\ \ units$$
Remaining work = 162 - 90 = 72 units
Now required days to complete 72 units =Â $$\frac{72}{24}=\ 3\ \ days.$$
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