Question 56

What is the value of: $$\frac{12  of  3 \div 6 + 12 \times 2 - (2 \times 4 - 5)}{12 \div 3 \times 4 + (2 \times 4 - 5)}$$?

Solution

= $$\frac{12\times\ \frac{3}{6}+24-(8-5)}{\frac{12}{3}\times4+(8-5)}$$

= $$\frac{6+24-3}{16+3}$$

= $$\frac{27}{19}$$


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