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Question 56
What is the value of: $$\frac{12 of 3 \div 6 + 12 \times 2 - (2 \times 4 - 5)}{12 \div 3 \times 4 + (2 \times 4 - 5)}$$?
Solution
=Â $$\frac{12\times\ \frac{3}{6}+24-(8-5)}{\frac{12}{3}\times4+(8-5)}$$
= $$\frac{6+24-3}{16+3}$$
= $$\frac{27}{19}$$
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