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The weights of two iron balls are 3.5 kg and 7.5 kg. What is the percentage weight of the 1st ball with respect to 2nd ball.
Weight of 1st ball = 3.5 kg and weight of second ball = 7.5 kg
=> Percentage weight of the 1st ball with respect to 2nd ball
= $$\frac{3.5}{7.5} \times 100$$
= $$\frac{35}{3} \times 4 = \frac{140}{3}$$
= $$46\frac{2}{3}\%$$
=> Ans - (A)
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