Question 56
P's salary is 25% higher than Q, what percentage is Q's salary lower than that of P?
Solution
Let Q's salary = Rs. $$100x$$
P's salary is 25% higher than Q, => P's salary = $$100x+(\frac{25}{100} \times 100x)=Rs.$$ $$125x$$
=> Q's salary is lower than that of P by = $$\frac{125x-100x}{125x} \times 100$$
= $$\frac{1}{5} \times 100=20\%$$
=> Ans - (A)
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