In a trapezium ABCD, AB and DC are parallel sides and $$\angle ADC = 90^\circ$$. If AB = 15 cm, CD = 40 cm and diagonal AC = 41 cm. Then the area of the trapezium ABCD is

A

245 $$cm^2$$

B

240 $$cm^2$$

C

247.5 $$cm^2$$

D

250 $$cm^2$$