If $$2 \cot \theta = 3$$, then find the value of $$\frac{\sqrt{13} \sin \theta - 3 \tan \theta}{3 \tan \theta + \sqrt{13} \cos \theta}$$

A

$$\frac{1}{\sqrt{13}}$$

B

$$\frac{2}{\sqrt{13}}$$

C

0

D

$$\frac{2}{3}$$