ABCD is a cyclic quadrilateral such that its sides AD and BC produced meet at P and sides AB and DC produced meet at Q. If $$\angle$$A = $$62^\circ$$ and $$\angle$$ABC = $$74^\circ$$, then the difference between $$\angle$$P and $$\angle$$Q is:

A

$$44^\circ$$

B

$$38^\circ$$

C

$$32^\circ$$

D

$$23^\circ$$