X is twice as good as workman as Y. Together, they finish the work in 18 days. In how many days can it be done by each separately?
Let the efficiency of Y = 1 unit per day.
Then, The efficiency of X = 2 units per day.
Total efficiency of A and Y together = 3 units per day.
Then, in 18 days, X and Y can do 18*3 = 54 units of work.
Hence, Total work = 54 units.
X can do the work individually in $$\dfrac{54}{2} = 27$$ days
Y can do the work individually in $$\dfrac{54}{1} = 54$$ days.
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