Solution
$$7\frac{1}{4} + [6 + (5 - 8 \div 4) - 1] = \dfrac{29}{4} + [6+(5-\dfrac{8}{4})-1]$$
$$= \dfrac{29}{4} + [6+5-2-1] = \dfrac{29}{4} + 8$$
$$= \dfrac{29+32}{4} = \dfrac{61}{4}$$
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