What is the greatest number of 4-digits which is divisible by 45, 25 and 5?

9000

$$9000\ \frac{\ 45}{ }=200$$

$$9000\ \frac{\ 25}{ }=360$$

$$9000\ \frac{\ 5}{ }=1800$$

9990

$$9990\ \frac{\ 45}{ }=222$$

$$9990\ \frac{\ 25}{ }=399.6$$

$$9990\ \frac{\ 5}{ }=1998$$

8900

$$8900\ \frac{\ 45}{ }=197.7$$

$$8900\ \frac{\ 25}{ }=356$$

$$8900\ \frac{\ 5}{ }=1780$$

9900

$$9900\ \frac{\ 45}{ }=220$$

$$9900\ \frac{\ 25}{ }=396$$

$$9900\ \frac{\ 5}{ }=1980$$

According to this Option D is the greatest 4 digit number which is multiple by 45,25 and 5.