$$\triangle$$ ABC is a right -angle triangle at B. If $$\tan A =\frac{5}{12}$$, then $$\sin A + \sin B + \sin C$$ will be equal to:

A

$$1\frac{5}{13}$$

B

$$2\frac{4}{13}$$

C

$$3\frac{1}{13}$$

D

$$2\frac{1}{13}$$