The number of non-negative real roots of $$2^x - x - 1 = 0$$ equals
Solution
$$2^x - x - 1 = 0$$ for this equation only 0 and 1 i.e 2 non-negative solutions are possible. Or we can plot the graph of $$2^x$$ and x+1 and determine the number of points of intersection and hence the solutin.
Yes, $$2^x = x+1$$ has the left hand side definitely positive, so $$x$$ has to be non- negative as well. Right away $$0$$ and $$1$$ satisfy. Know that the curves will only intersect at two points (you don’t need to draw them to have this intuition).
Hope this helps, feel free to ask if you have any doubts