Let $$\triangle ABC \sim \triangle PQR$$ and $$\frac{ar\left(\triangle ABC\right)}{ar\left(\triangle QPR\right)} = \frac{64}{169}$$. If AB = 10 cm, BC = 7 cm and AC = 16 cm, then PR (in cm) is equal to:

A

21

B

26

C

15

D

13