Solution
Given, $$x+\frac{4}{x}-4=0$$
$$\Rightarrow$$ $$x^2+4-4x=0$$
$$\Rightarrow$$ $$\left(x-2\right)^2=0$$
$$\Rightarrow$$ $$x-2=0$$
$$\Rightarrow$$ $$x=2$$
$$\therefore\ $$ $$x^2-4=2^2-4=4-4=0$$
Hence, the correct answer is Option A
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