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If $$\frac{8x+3y}{4x+5y}=\frac{25}{23}$$ then find $$x:y$$.
By applying componendo and dividendo we have (a/b)=c/d then (a+b)/(a-b) =(c+d)/(c-d)
12x+8y/4x-2y =48/2
6x+4y=48x-24y
28y=42x
x:y=2:3
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