An equilateral triangle with side a units is cut on the vertices to make it a regular hexagon. What is the area of the hexagon?

A

$$\frac{3a^{2}}{2\sqrt{3}}$$ square units

B

$$\frac{2a^{2}}{3\sqrt{3}}$$ square units

C

$$\frac{2a^{2}}{\sqrt{3}}$$ square units

D

$$\frac{a^{2}}{2\sqrt{3}}$$ square units