Question 54

Whatis the area of a triangle whose sides are 7 cm, 24 cm and 25 cm?

Solution

If we look at the given sides, it satisfies the pythogarus theorem, which is $$side^2 + side^2 = hypotnuse^2$$

= $$7^2 + 24^2 = 25^2$$

=> $$49+576 = 625$$

Hence it would be a right angled triangle.

Area of a right angled triangle = $$\frac{base \times height}{2}$$

Here longer side would be hypotenuse

So, Area = $$\frac{base \times height}{2}$$

$$\frac{7 \times 24}{2}$$

=84 $$cm^{2}$$

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