What is the area of a triangle whose sides are 3 cm, 5 cm and 4 cm?
By triplet 3-4-5, the triangle will be right angle triangle so,
5 will be hypotenuse.
Area of triangle = $$\frac{1}{2} \times base \times height =Â Â \frac{1}{2} \times 3 \times 4 = 6 cm^2$$
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