Question 54

The sum of two digits of a number is 10. If the digits are interchanged, then its value increases by 18. Find the number.

Solution

Let the digits at unit place be y and tens place be x

x + y = 10 --------I

Number formed = 10x + y and number formed after digits interchnaged = 10y + x

According to the question,

(10y+x) - (10x+y) = 18

10y + x - 10x - y = 18

9y - 9x = 18

y - x = 2  ----------II

Adding I and II we get

2y = 12

y = 6 and x = 4

Hence, number = $$10\times\ 4+6=46$$


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