Question 54
The average of 15 different natural numbers is 13. The maximum value of the second largest of these nubers is
Solution
Let first natural number = a
Second natural number = a + 1
15th natural number = a + 14
According to the question:
$$\frac{a + a + 1 + a + 2 + ........... + a + 14}{15} = 13$$
15a + 105 = 195
a = 6
Second largest of these nubers = a + 13 = 19
