If the corresponding angles of two triangles are equal and satisfy $$\frac{PX}{ER}=\frac{ZX}{RF}=\frac{PZ}{EF}$$, then:

A

$$\triangle$$ PXZ is similar to $$\triangle$$ EFR

B

$$\triangle$$ PXZ is similar to $$\triangle$$ ERF

C

$$\triangle$$ XPZ is similar to $$\triangle$$ ERF

D

$$\triangle$$ PXZ is similar to $$\triangle$$ REF